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The weights of a certain dog breed are approximately normally distributed with a mean of μ= 52 pounds, and a standard deviation of σ= 7 pounds.

The weights of a certain dog breed are approximately normally distributed with a mean-example-1

1 Answer

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Z-Score: z = (x - μ) / σ

a) z = (53 - 52) / 7

z = 1/7 ≈ 0.14

b) -1.51 = (x - 52) / 7

x = -1.51 (7) + 52 ≈ 41.4 lbs.

c) 1.51 = (x - 52) / 7

x = 1.51 (7) + 52 ≈ 62.6 lbs.

answered
User Garrett Kadillak
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