asked 158k views
1 vote
Giving a test to a group of students, the grades and gender are summarized below

A B C Total
Male 18 16 14 48
Female 17 7 4 28
Total 35 23 18 76
If one student was chosen at random, determine the following probabilities. Write your answers as reduced fractions.

P
P
(Student was male) =
P
P
(Student was female) =
P
P
(Student was male and got an "A") =
P
P
(Student was female and got a "B") =
P
P
(Student got a "C") =

2 Answers

4 votes

To determine the probabilities, we can use the provided data on grades and gender. Let's calculate each probability step by step:

P(Student was male) = Number of male students / Total number of students

P(Student was male) = 48 / 76

P(Student was male) = 6/19

P(Student was female) = Number of female students / Total number of students

P(Student was female) = 28 / 76

P(Student was female) = 7/19

P(Student was male and got an "A") = Number of male students who got an "A" / Total number of students

P(Student was male and got an "A") = 18 / 76

P(Student was male and got an "A") = 9/38

P(Student was female and got a "B") = Number of female students who got a "B" / Total number of students

P(Student was female and got a "B") = 7 / 76

P(Student was female and got a "B") = 7/76

P(Student got a "C") = Number of students who got a "C" / Total number of students

P(Student got a "C") = 18 / 76

P(Student got a "C") = 9/38

So the probabilities are:

P(Student was male) = 6/19

P(Student was female) = 7/19

P(Student was male and got an "A") = 9/38

P(Student was female and got a "B") = 7/76

P(Student got a "C") = 9/38

answered
User Pforhan
by
7.3k points
2 votes

Answer:

Explanation:

1.)

#males/#studnets

48/76= 12/19

2.)

#females/#students

28/76= 7/19

3.)

#students who are male and got an A / #students

18/76= 9/38

4.)

#students who got a B and are female / #students

7/76= 7/76

5.)

#students who got a C/ #students

18/76= 9/38

answered
User Jocke Med Kniven
by
8.2k points

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