Question

find the area of the figure below.composed of an isosceles trapezoid and one semicircle.rounded to the nearest tenths place

Answer 1

Answer: 33.6 units squared

Step by Step Step-by-step explanation:

Area of Trapezoid

A=1/2×(base 1+ base 2)(height)

=1/2×(14+2)(4)

=1/2×(16)(4)

Cancel:

=16 and 2 can be cancelled to 8 and 1

Since the fraction is 1/1 it is not needed

=8×4

=32 units squared

Area of Half-Circle:

A=1/2πr×r(pie×radius squared)

=1/2π×diameter÷2×the number

=1/2π×1×1

=1/2π

=1.6 units squared

Total Area:

32+1.6

=33.6 units squared