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What volume, in liters, will 6.88 × 102 g of air occupy if the density of air is 1.29 g/L? Express your answer in scientific notation

asked
User Eric Tan
by
8.6k points

1 Answer

5 votes

Answer:

Step-by-step explanation:

To find the volume of 6.88 × 10^2 g of air, we can use the formula:

Volume = Mass / Density

Given:

Mass = 6.88 × 10^2 g

Density = 1.29 g/L

Volume = (6.88 × 10^2 g) / (1.29 g/L)

Dividing the mass by the density:

Volume ≈ 533.33 L

Expressing the answer in scientific notation:

Volume ≈ 5.3333 × 10^2 L

answered
User Gndps
by
8.2k points

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