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A company is designing a new cylindrical water bottle. The volume of the bottle will be 158 cm^3. The height of the water bottle is 8.3 cm. What is the radius of the water​ bottle? Use 3.14 for pie

asked
User Djohon
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7.8k points

2 Answers

6 votes

Answer: Around 2.46 cm.

Explanation:

The volume for a cylinder is volume = πr^2 x h

Substitute the variables
158 = 3.14 x r^2 x 8.3

Simplify the right side (multiple 3.14 x 8.3) to get 158 = r^2 x 26.062

Divide both sides by 26.062 to get approximately 6.06 = r^2

To get rid of the exponent, take the square root of 6.06, which is around 2.46.

answered
User Rizwan Ali
by
7.7k points
2 votes
The volume of a cylindrical water bottle can be calculated using the formula:

V = πr^2h

where V is the volume, r is the radius, h is the height, and π is approximately 3.14.

In this case, we are given that the volume of the water bottle is 158 cm^3 and the height is 8.3 cm. We can substitute these values into the formula and solve for the radius:

158 = 3.14r^2(8.3)

Divide both sides by (3.14)(8.3) to isolate r^2:

r^2 = 158 / (3.14)(8.3)

r^2 ≈ 6.0

Take the square root of both sides to find r:

r ≈ √6.0

r ≈ 2.45 cm

Therefore, the radius of the water bottle is approximately 2.45 cm.
answered
User Joe Wood
by
8.5k points

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