Question

5. Points P(3,0) and Q(-3,4) are on the line ax + by=6 find the value of a and b​

Answer 1

• a = 2, b = 3

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Substitute the coordinates of each point and solve the formed system:

• a*3 + b*0 = 6 ⇒ 3a = 6 ⇒ a = 2
• a(- 3) + b*4 = 6 ⇒ - 3a + 4b = 6 ⇒ -6 + 4b = 6 ⇒ 4b = 12 ⇒ b = 3

So the value of coefficients is a = 2, b = 3.