Question

Help me please i need You help ​

Answer 1

Answer: Factoring the polynomial gets you 4(v-2)(v+1)

Explanation:

(You did not clarify what you needed done here. This problem looks like a factor one, so that's what I assumed. Apologies if that's not the case.)

Answer 2

To solve the quadratic equation 4v² - 4v - 8, we can use the quadratic formula:

v = (-b ± √(b² - 4ac)) / (2a)

In this case, the coefficients are:

a = 4

b = -4

c = -8

Substituting these values into the formula, we get:

v = (-(-4) ± √((-4)² - 4(4)(-8))) / (2(4))

v = (4 ± √(16 + 128)) / 8

v = (4 ± √144) / 8

v = (4 ± 12) / 8

Simplifying further, we have:

v₁ = (4 + 12) / 8 = 16 / 8 = 2

v₂ = (4 - 12) / 8 = -8 / 8 = -1

Therefore, the solutions to the equation 4v² - 4v - 8 are v = 2 and v = -1.