Answer:
Step-by-step explanation:
In a cross between a female fruit fly that is homozygous dominant for red eyes (XX) and a male fruit fly with white eyes (XwY), where eye color is a sex-linked trait in fruit flies, the resulting offspring can be determined using a Punnett Square.
The Punnett Square for this cross would look as follows:
| X w
-----------------
X | XX Xw
X | XX Xw
Y | XY Yw
In this case, all of the female offspring (XX) will have red eyes because they inherit a dominant red eye allele from the homozygous dominant female parent. On the other hand, the male offspring will inherit their eye color from their mother and will have a 50% chance of having red eyes (XY) and a 50% chance of having white eyes (XwY).
Therefore, the phenotypic percentages of the offspring would be:
50% of the offspring will have red eyes (females: XX, males: XY)
50% of the offspring will have white eyes (males: XwY)
It's important to note that in this case, since eye color is a sex-linked trait and the male parent has white eyes, all the male offspring will have white eyes. The red eye color allele is located on the X chromosome, and since the male offspring receive their X chromosome from their mother, they will inherit the white eye allele from their father.