Question

In PQR, Q = 76, PQ = 18, and QR = 27
Can you help me with 5!

Answer 1

The answer is

m<p =66°21'14"

m<R =37°38'46"

PR =28,6

Explanation:

`{pr}^(2) = {18}^(2) + {27}^(2) - 2 * 18 * 27 \cos(76) = 817.85 \\ pr = 28.6 \\ \cos(p) = \frac{ {18}^(2) + {28.6}^(2) - { {27}^(2) } }{2 * 18 * 28.6 } = 0.4 \\ m < p = 66.42 \\ m < r = 180 - 76 - 66.42 = 37.58`