Question

Solve this quadratic equation using the quadratic formula.x²-6x+6=0

A.x=3±√3
B.x=-6±√6
C.x=-3±√3
D.x=6±√6

Answer 1

X = [-b +/- square root (b^2 -4ac)] / 2a
a = 1
b = -6
c = 6
X = [-(-6) +/- square root (-6^2 -4(1)(6))] / 2(1)
= [6+/- square root (36-24)]/2
= [6+/- square root (12)] /2
= 3 +/- [(square root 12)/ 2]
= 3 +/- square root 3
Answer is A