Question

Sodium metal reacts with water to produce NaOH according to the following equation:

2Na + 2H2O → 2NaOH + H2
How many grams of NaOH are produced if 20.05 g of sodium metal react with excess oxygen?

Answer 1

34.84 g

Step-by-step explanation:

2Na + 2H2O → 2NaOH + H2
2 moles of Na reacts with 2 moles of H2O to produce 2 moles of NaOH and 1 mole of Hydrogen

We're given 20.05 g of Na (0.871 mol) in excess of oxygen, which makes Na the limiting reagent.

So, if 2 moles of Na are required to produce 2 moles of NaOH
0.871 moles of Na can produce 0.871 moles of NaOH
Now, we can find the weight of NaOH = moles * molecular mass
= 0.871 * 40
= 34.84 g