Question

Consider this equation.

Answer 1

B

Explanation:

given

tanΘ =
`(3√(5) )/(2)` =
`(opposite)/(adjacent)`

this ratio relates to a right triangle, with hypotenuse h and

legs 3
`√(5)` and 2

using Pythagoras' identity in the right triangle

h² = (3
`√(5)` )² + 2² = 45 + 4 = 49 ( take square root of both sides )

h =
`√(49)` = 7

then

cosΘ =
`(adjacent)/(hypotenuse)` =
`(2)/(7)`