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How to condense 7logx + 6logy - 2log3

1 Answer

2 votes

Answer:

log(x^7·y^6/9)

Explanation:

You want to write 7log(x) +6log(y) -2log(3) as a single logarithm.

Rules of logs

The relevant rules of logarithms are ...

log(ab) = log(a) +log(b)

log(a^b) = b·log(a)

log(a/b) = log(a) -log(b)

Application

Using these rules, we can combine the logarithms as follows:

7log(x) +6log(y) -2log(3)

= log(x^7) +log(y^6) -log(3^2)


\log\left((x^7y^6)/(9)\right)

<95141404393>

answered
User RithwikBojja
by
8.3k points

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