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2 votes
The specific heat capacity of zinc 0.386 J/g °C. How many joules would be released when 156 grams of zinc at 28.0°C were heated to 96.0 °C?

1 Answer

4 votes

Answer:

The following data were obtained from the question:

Specific heat capacity (C) = 0.386 J/gºC

Mass (m) = 156 g

Initial temperature (T1) = 96.0ºC

Final temperature (T2) = 28.0ºC

Change in temperature (ΔT) = T1 – T2 = 96 – 28 = 68°C

Heat (Q) =..?

The heat released can be obtained as follow:

Q = m * c * ΔT

= 156 g * 0.386 J/g °C * 68.0 °C

≈ Q = m * c * ΔT

= 156 g * 0.386 J/g °C * 68.0 °C

≈ 3977.568 J

Therefore, the heat released is 3977.568 J

Step-by-step explanation:

answered
User Brian Crist
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