Answer:
The following data were obtained from the question:
Specific heat capacity (C) = 0.386 J/gºC
Mass (m) = 156 g
Initial temperature (T1) = 96.0ºC
Final temperature (T2) = 28.0ºC
Change in temperature (ΔT) = T1 – T2 = 96 – 28 = 68°C
Heat (Q) =..?
The heat released can be obtained as follow:
Q = m * c * ΔT
= 156 g * 0.386 J/g °C * 68.0 °C
≈ Q = m * c * ΔT
= 156 g * 0.386 J/g °C * 68.0 °C
≈ 3977.568 J
Therefore, the heat released is 3977.568 J
Step-by-step explanation: