Question

What is the equation of the circle with center (0,0) that passes through the point (-6,-6)? need answers right now

O(x+6)² + (y+6)² = 72
0x² + y² = 0
O x² + y² = 72
○(x+6)² + (y+6)² = 0​

Answer 1

The equation of a circle with center (0,0) that passes through the point (-6,-6) is:

(x - 0)² + (y - 0)² = r²

where r is the radius of the circle. Since the center of the circle is (0,0), we can use the distance formula to find the radius:

r = √(0 - (-6))² + (0 - (-6))² = √(6² + 6²) = √72

Therefore, the equation of the circle is:

x² + y² = 72

Answer 2

The correct equation of the circle with center (0,0) that passes through the point (-6,-6) is:

(x + 6)² + (y + 6)² = 72

Please note that the equation represents the circle with center (0,0) and radius √72.