Question

Question 1 An object of mass 20kg accelerates from rest to a velocity of 10m/s in 5 sec. calculate the distance covered by the object ​

Answer 1

25 m

Step-by-step explanation:

Let's assume that its acceleration is constant. We can determine the acceleration of the object by its definition

`a= (\Delta v)/(\Delta t) = (10-0(\frac ms))/(5 s) = 2 \frac m{s^2}`

Now we can write the equation of motion

`s(t)= s_0 + v_0t + \frac12at^2`

where, the two terms
`s_0\ v_0` represent the initial position and velocity respectively. Replacing the values we have ("from rest" means that initial velocity is 0)

`s(5) = 0+0(5)+\frac12 2 (5)^2 = 25 m`