Final answer:
The ground-state electron configuration of lead (Pb) is [Xe]6s2 4f145d106p2. This follows the electron-filling order of the Aufbau principle, with xenon (Xe) as the nearest noble gas. So the correct option is B.
Step-by-step explanation:
The question asks for the ground-state electron configuration of lead (Pb). To find the correct option, we need to look at the choices provided and deduce which one matches the correct electron filling order following the Aufbau principle, Hund's rule, and the Pauli exclusion principle.
Lead (Pb) has an atomic number of 82. The nearest noble gas before lead is xenon (Xe), which has an atomic number of 54. From xenon, we would count up the electrons to lead:
- The 6s subshell will be filled with 2 electrons.
- Since lead is a post-transition metal, the 4f and 5d subshells will be filled next. The 4f subshell can accommodate 14 electrons and the 5d subshell can accommodate 10 electrons.
- Finally, the 6p subshell will have 2 electrons, as Pb is in the p-block of the periodic table.
Therefore, the ground-state electron configuration of Pb is [Xe]6s24f145d106p2, which corresponds to option B: [Xe]6s24f145d106p2.