Question

What is the vertex of f(x)=x^2−10x+16 ?

Answer 1

coordinates for vertex are (5, -9)

Explanation:

Given

`a=1\\\\b=-10\\\\c=16`

using the formula for the x coordinate of the vertex which is
`(-b)/(2a)` it yields:

`x_(vertex)=(-(-10))/(2)=5`

We now have the x-coordinates of the vertex, by applying the x coordinate in the equation we get:

`5^2-(10* 5)+16\\\\=25-50+16\\\\=-9`

thus the
`y_(vertex)=-9`

Thus the coordinates of the vertex should be (5, -9)