Question

I would appreciate help without guessing :)

Answer 1

Definitely not underfined

Answer 2

a)
`\sqrt{56` → Definitely not undefined because 56 is a positive real number

b)
`-\sqrt{56` → Definitely not undefined because 56 is a positive real number (and the negative sign is not under the square root)

c)
`\sqrt{-56` → Definitely undefined because -56 is a negative number

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We know that there is no real square root of a negative number because nothing multiplied by itself results in a negative number.

__

d)
`\sqrt h` → Could be undefined because we don't know the value of
`h`; it could be positive or negative

e)
`-\sqrt {h` → Could be undefined because we don't know the value of
`h`; it could be positive or negative (and the negative sign doesn't affect this because it is outside the square root)

f)
`\sqrt{-h` (when
`h` is positive) → Definitely undefined because the value inside of the square root is negative (a negative times a positive is a negative)