Question

An object is placed 15 cm in front of a diverging lens whose focal length is 12 cm. Where will the image be located ( in cm) ? A) -6.7. B) -7.2. C) -0.15.

Answer 1

A) -6.7 cm

Step-by-step explanation:

An object is placed 15 cm in front of a diverging lens (concave lens)
So u = -15 cm
and f = -12 cm (also given)
So, using the lens formula 1/f = 1/v - 1/u,
1/v = 1/f + 1/u
= [1/(-12)] + [1/(-15)]
= -3/20
So, v = -20/3 = -6.67 or ≈ -6.7 cm