The work function of the metal is 0.45 x 10⁻¹⁹ J. In a photoelectric effect experiment, the work function of a metal refers to the minimum amount of energy required to release an electron from the metal's surface.
In this experiment, the metal is illuminated with light of a specific wavelength (330 nm). The energy of the photons in the light is given by E = hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength of the light.
The stopping potential (0.85 V) is the minimum potential required to stop the electrons from reaching the collector. The kinetic energy of the electrons is given by K = eV, where e is the electron charge and V is the stopping potential. The energy of the incident photons must be greater than the work function of the metal for electrons to be released, and the kinetic energy of the electrons must be less than the energy of the incident photons.
Using these equations, we can solve for the work function of the metal. First, we find the energy of the incident photons: E = hc/λ = (6.626 x 10⁻³⁴J s)(3.00 x 10⁸ m/s)/(330 x 10⁻⁹ m) = 1.81 x 10⁻¹⁹ J.
Next, we use the equation K = eV to find the maximum kinetic energy of the electrons: K = eV = (1.60 x 10⁻¹⁹ C)(0.85 V) = 1.36 x 10⁻¹⁹J.
Finally, we can solve for the work function by subtracting the maximum kinetic energy from the energy of the incident photons: Φ = E - K = (1.81 x 10⁻¹⁹J) - (1.36 x 10⁻¹⁹ J) = 0.45 x 10⁻¹⁹ J.
Therefore, the work function of the metal is 0.45 x 10⁻¹⁹ J.
The full question is:
In a photoelectric effect experiment you illuminate a metal with light of wavelength 330 nm and measure a stopping potential of 0.85 v. what is the work function of the metal?