Question

if 3.41 g of nitrogen react with 2.79 g of hydrogen to produce ammonia, what is the limiting reactant and what mass of ammonia is produced?if 3.41 g of nitrogen react with 2.79 g of hydrogen to produce ammonia?

Answer 1

Step-by-step explanation:

N2 + 3H2 —————-> 2NH3

Mass of nitrogen = 3.41 g

Mass of hydrogen = 2.79 g

Change it into moles

No of moles (N2) = (mass in grams)/molar mass

No of moles (N2) = 3.14/14 = 0.22 mol

No of moles (H2) = 2.79/2 = 1.4 mol

Than we find which moles produce less moles of NH3

According to equation

1 mole nitrogen produce NH3 = 2 mol

0.22 mole nitrogen produce NH3 = 2 x 0.22 = 0.44

3 mole hydrogen produce NH3 = 2 mol

1 mole hydrogen produce NH3 = 2/3 = 0.67 mol

1.4 mole hydrogen produce NH3 = 0.67x 1.4= 0.93 mol

So

nitrogen produce NH3 = 0.44 mol

Hydrogen produce NH3 = 0.93 mol

So nitrogen produce less moles of NH3 so it is limiting reactant.

In that reaction 0.44 mol ammonia is produced