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Consider the line 6x-4y=-8

A) Find the equation of the line that is perpendicular to this line and passes through the point (4,-6).

b) Find the equation of the line that is parallel to this line and passes through the point(4,-6).

1 Answer

6 votes

Answer:

(A) The equation of the line perpendicular to the line 6x - 4y = -8 and passes through (4, -6) is y = -2/3x - 10/3

(B) The equation of the line that is parallel to the line 6x - 4y = -8 and pases through (4, -6) is y = 3/2x - 12

Explanation:

(A)

  • The slopes of perpendicular lines are negative reciprocals of each other, as shown by the formula m2 = -1 / m1, where
  • m2 is the slope of the line we don't know,
  • and m1 is the slope of the line we're given.

Currently, 6x - 4y = -8 is in standard form, but we can convert it to slope-intercept form (y = mx + b with the slope being m) by isolating y:

Step 1: Subtract 6x from both sides:

(6x - 4y = -8) - 6x

-4y = -6x - 8

Step 2: Divide both sides by -4 to isolate y and find the slope-intercept form:

(-4y = -6x - 8) / -4

y = (-6x) / -4 + (-8) / -4

y = 3/2x + 2

Thus, the slope of the line we're given (aka m1 in the perpendicular slope formula) is 3/2.

Step 3: Now we can plug in 3/2 for m1 in the perpendicular slope formula to find m2, the slope of the other line:

m2 = -1 / (3/2)

m2 = -1 * 2/3

m2 = -2/3

Thus, the slope of the other line is -2/3

Step 4: We can keep using the slope-intercept form to find b, the y-intercept of the line. To do this, we must plug in (4, -6) for x and y and -2/3 for m, allowing us to solve for b:

y = mx + b

-6 = 4(-2/3) + b

-6 = -8/3 + b

-10/3 = b

Thus, the equation of the line perpendicular to the line 6x - 4y = -8 and passes through (4, -6) is y = -2/3x - 10/3

(B)

  • The slopes of parallel lines are equal to each other, as shown by the formula m2 = m1, where
  • m1 is the slope we're given,
  • and m2 is the slope of the other line

Step 1: We already know that m1 is 3/2 so m2 is also 3/2. Thus, the slope of the other line is 3/2

Step 2: We can use the slope-intercept form to find b, the y-intercept of the other line. To do this, we must plug in (4, -6) for x and y and 3/2 for m, allowing us to solve for b:

y = mx + b

-6 = 3/2(4) + b

-6 = 12/2 + b

-6 = 6 + b

-12 = b

Thus, the equation of the line that is parallel to the line 6x - 4y = -8 and passes through (4, -6) is y = 3/2x - 12

answered
User Unni Babu
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