Question

it took 56mL of H2CO3 to change the Ca(OH)2 from pink to clear. the molarity of the H2CO3 was 3M. The molarity of Ca(OH)2 is under termed. the initial volume of liquid in the flask was 150mL. What is the molarity of Ca(OH)2?

Answer 1

The balanced chemical equation for the reaction between H2CO3 and Ca(OH)2 is:

H2CO3 + Ca(OH)2 -> CaCO3 + 2H2O

From the equation, we can see that 1 mole of H2CO3 reacts with 1 mole of Ca(OH)2.

The number of moles of H2CO3 used in the reaction can be calculated using the formula:

moles H2CO3 = Molarity x Volume (in liters)

= 3 M x 0.056 L

= 0.168 moles

Since 1 mole of H2CO3 reacts with 1 mole of Ca(OH)2, the number of moles of Ca(OH)2 is also 0.168 moles.

The volume of the solution is 150 mL = 0.150 L.

Molarity of Ca(OH)2 = moles of Ca(OH)2 / volume of solution (in liters)

= 0.168 moles / 0.150 L

= 1.12 M

Therefore, the molarity of Ca(OH)2 is 1.12 M.

Step-by-step explanation: