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What is the area of the triangle whose vertices are A (0, 0) B(-10, 0) and C(0, -6)

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User Nxn
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1 Answer

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We can find the area of the triangle using the formula:

A = 1/2 * base * height

where the base is the distance between points A and B, and the height is the distance between point C and the line containing points A and B.

The distance between points A and B is:

AB = |-10 - 0| = 10

The line containing points A and B is the x-axis, so the height of the triangle is the y-coordinate of point C, which is 6 units away from the x-axis. Therefore, the height is:

h = 6

The area of the triangle is:

A = 1/2 * base * height
A = 1/2 * 10 * 6
A = 30 square units

Therefore, the area of the triangle whose vertices are A (0, 0), B(-10, 0), and C(0, -6) is 30 square units.
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User Kelgwiin
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