Answer:
Point where the line crosses the y-axis is (0, -8)
Gradient: 3
Explanation:
The slope-intercept form of the equation of a straight line is
y = mx + b
where m =slope or gradient
b is the y-intercept ie the y-value where the line crosses the y-axis. This is also the value of y when x = 0
Comparing the general equation with y = 3x - 8
we get the y-intercept as -8 and therefore the point (0, -8) is the point where the line crosses the y-axis
The gradient is 3 which is the coefficient of x