Answer:
2 more of the smaller cans will fit on the shelf than the larger can.
Explanation:
To solve this problem, we need to know the dimensions of the cans and the width of the shelf. Let's assume that the smaller can have a diameter of 8 cm and a height of 10 cm, while the larger can have a diameter of 10 cm and a height of 12 cm. We also know that the shelf is 1 meter wide, or 100 cm.
First, let's calculate the volume of each can:
The smaller can have a radius of 4 cm and a height of 10 cm, so its volume is π × 4² × 10 = 502.65 cm³.
The larger can have a radius of 5 cm and a height of 12 cm, so its volume is π × 5² × 12 = 942.48 cm³.
Next, let's calculate how many of each can will fit on the shelf:
To fit on the shelf, the cans must be arranged side by side, with no gaps between them. Assuming that the cans are perfectly cylindrical, we can calculate how many will fit by dividing the width of the shelf by the diameter of each can.
The smaller can have a diameter of 8 cm, so 100 cm ÷ 8 cm = 12.5 cans can fit on the shelf.
The larger can have a diameter of 10 cm, so 100 cm ÷ 10 cm = 10 cans can fit on the shelf.
Finally, let's calculate the difference in the number of cans that will fit:
The number of smaller cans that will fit is 12.
The number of larger cans that will fit is 10.
The difference is 12 - 10 = 2.
Therefore, 2 more of the smaller cans will fit on the shelf than the larger can.