asked 230k views
0 votes
Draw a graph of y=log_1/3 (x) and its inverse on the same pair of axis.

asked
User Talley
by
7.4k points

1 Answer

4 votes

The graph of y = log1/3(x) is a decreasing curve that passes through the points (1, 0) and (3, -1). The horizontal asymptote is y = 0, and the vertical asymptote is x = 0.

The inverse of y = log1/3(x) is x = 3^y, which is equivalent to y = log3(x). The graph of y = log3(x) is an increasing curve that passes through the points (1, 0) and (3, 1). The horizontal asymptote is y = 0, and the vertical asymptote is x = 0.

When both graphs are plotted on the same pair of axis, they intersect at the point (1, 0) and (3, -1) and (3, 1).

answered
User Horstling
by
8.5k points

Related questions

asked Sep 24, 2024 27.4k views
Mvc asked Sep 24, 2024
by Mvc
8.4k points
1 answer
0 votes
27.4k views
asked Dec 23, 2024 79.9k views
Ric W asked Dec 23, 2024
by Ric W
7.6k points
1 answer
2 votes
79.9k views
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.