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I have the bottom one right but I need help with the first question please.

I have the bottom one right but I need help with the first question please.-example-1

1 Answer

2 votes

Answer:

1 = (x/11)² +24y²/605

Explanation:

You want the the equation of an ellipse through the point (1, 5) with ends of its major axis at (±11, 0).

Ellipse equation

The ellipse equation will have the form ...

(x/11)² + (y/b)² = 1

for some value 'b' that causes (x, y) = (1, 5) to be a solution to this equation.

Value of b

Using the given point and solving for b (or b²), we have ...

(1/11)² +(5/b)² = 1

25/b² = 1 -1/121 = 120/121

Inverting this equation and multiplying by 25, we have ...

b² = 605/24

Equation of interest

Using this value for b², we can write the equation of the ellipse as ...


\boxed{1=(x^2)/(121)+(24y^2)/(605)}

<95141404393>

I have the bottom one right but I need help with the first question please.-example-1
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User Yulette
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