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What is the intermediate step in the form(x+a)^2=b as a result of completing the square for the following equation?

X^2-8x+32=12x-4

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Answer:

To complete the square for the equation X^2-8x+32=12x-4, we first need to move all the constant terms to one side of the equation and all the variable terms to the other side.

X^2 - 8x - 12x + 32 = -4

Next, we can simplify the equation by combining like terms:

X^2 - 20x + 32 = -4

Then, we can add a constant term to both sides of the equation such that the left side becomes a perfect square trinomial:

X^2 - 20x + 100 = 64

Finally, we can write the left side of the equation in the form (x - a)^2, where a is a constant:

(X - 10)^2 = 64

Therefore, the intermediate step in the form (x + a)^2 = b as a result of completing the square for the equation X^2 - 8x + 32 = 12x - 4 is (X - 10)^2 = 64.

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