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HELP!! PLS

Find the values of x and y in parallelogram PQRS.
PT=y, TR= 2x + 1, QT=3y. TS = 3x +9

HELP!! PLS Find the values of x and y in parallelogram PQRS. PT=y, TR= 2x + 1, QT-example-1

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Explanation:

In a parallelogram, opposite sides are equal and parallel. Therefore,

QT = PS = 3y ...(1)

PT + TR = PS

y + 2x + 1 = 3x + 9

2x - y = 4 .....(2)

PR = QT = 3y

PR = SQ = 3x + 9 ....(3)

From equations (1) and (3), we can see that:

3y = 3x + 9

y = x + 3

Substitute this value of y in equation (2):

2x - (x + 3) = 4

x = 7

To find the value of y, we can substitute x = 7 in equation (2):

2(7) - y = 4

y = 10

Therefore, x = 7 and y = 10.

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