Question

Please help and show work :)

A housecat accelerates (from rest) at 0.21 m/s^2 for 7 seconds. How fast is the cat going after 7 seconds? Hint: look at the kinematic equations.

Answer 1

1.47 m/s

Step-by-step explanation:

v = v0 + at

where

v0 = initial velocity (zero in this case)

a = acceleration = 0.21 m/s^2

t = time = 7 seconds

Plugging in these values, we get:

v = 0 + (0.21 m/s^2)(7 s)

v = 1.47 m/s