Question

What is the binding energy in kJ/mol nucleons for bromine-79? kJ/mol nucleons 79 35Br The required masses (g/mol) are:1H 1.00783 ;İn 1.00867 ;,:Br-78.91 830 . 79 Submit Answer Retry Entire Group 9 more group attempts remaining

Answer 1

The binding energy in kJ/mol nucleons for bromine-79 can be calculated by converting the atomic mass, finding the number of nucleons, and converting the MeV value to kJ/mol nucleons.

Step-by-step explanation:

The binding energy in kJ/mol nucleons for bromine-79 is calculated as follows:

1. Convert the atomic mass of bromine-79 from g/mol to kg/mol by dividing it by 1000.
2. Multiply the atomic mass by Avogadro's number to find the number of nucleons in one mol of bromine-79.
3. Divide the binding energy per nucleon (493.9 MeV) by 1.602 x 10^-13 to convert it to kJ/mol nucleons.

Therefore, the binding energy in kJ/mol nucleons for bromine-79 is ____ kJ/mol nucleons.

Answer 2

The binding energy per nucleon for bromine-79 is 6.23 MeV/nucleon.

Step-by-step explanation:

The binding energy per nucleon for bromine-79 (7935Br) is calculated by dividing the total nuclear binding energy by the number of nucleons. The binding energy for bromine-79 is 492 MeV and the number of nucleons is 79. Therefore, the binding energy per nucleon is 492 MeV / 79 nucleons = 6.23 MeV/nucleon.