a) If the bride must be in the picture, we have to choose 5 people from the remaining 9 guests. We can do this in 9 choose 5 ways, which is:
nCr(9, 5) = 126 ways
b) If the bride but not the groom must be in the picture, we have to choose 1 person from the groom and 5 people from the remaining 8 guests. We can do this in 8 choose 5 ways, which is:
nCr(8, 5) = 56 ways
c) If the bride and groom must both be in the picture, we have to choose 4 people from the remaining 8 guests. We can do this in 8 choose 4 ways, which is:
nCr(8, 4) = 70 ways
d) If neither the bride nor the groom can be in the picture, we have to choose 6 people from the remaining 8 guests. We can do this in 8 choose 6 ways, which is:
nCr(8, 6) = 28 ways
e) If exactly one of the bride or groom is to be in the picture, we can choose the bride and 5 people from the remaining 8 guests, or the groom and 5 people from the remaining 8 guests. The number of ways to do this is:
nCr(8, 5) + nCr(8, 5) = 2 * nCr(8, 5) = 2 * 56 = 112 ways
Therefore, the answers are:
a) 126 ways
b) 56 ways
c) 70 ways
d) 28 ways
e) 112 ways