Answer:
When sulfuric acid is placed in a beaker containing potassium hydroxide, a double displacement reaction occurs. In a double displacement reaction, the ions of two compounds are exchanged to form two new compounds. In this case, the hydrogen ions from sulfuric acid are exchanged with the hydroxide ions from potassium hydroxide to form water and potassium sulfate.
The balanced chemical equation for this reaction is:
H2SO4(aq) + 2KOH(aq) → 2H2O(l) + K2SO4(aq)
As you can see from the equation, 2 water molecules are formed for every mole of sulfuric acid and potassium hydroxide that react.