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suppose that is normally distributed with mean 110 and standard deviation 26. a. what is the probability that is greater than 146.14?

1 Answer

1 vote

Answer:

0.0823

Explanation:

we need to find z-score by using z-table and the formula, z = (x - υ) / υ where x is the observed value, υ is the mean and υ is the standard deviation.

z = (146.14 - 110) / 26

= 1.39.

now find the area relating to this z-score of 1.39 on a z-table.

go down the left column until to come to +1.3.

now find 0.09 on top row.

look where 1.3 and 0.09 meet.

the number is 0.9177.

that is the area to the left of z = 1.39. but we want area to right (question says probability it is greater).

total area under a bell curve (normal distribution) ALWAYS equals 1.

so area to right of z =1.39 is

1 - 0.9177

= 0.0823.

probability it is greater than 146.14 is 0.0823

answered
User Mwallner
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