Question

a power supply maintains a potential difference of 58.1 v across a 1750 ω resistor. what is the current in the resistor

Answer 1

`\huge\boxed{\sf I \approx 0.03 \ A}`

Step-by-step explanation:

Given data:

Potential difference = v = 58.1 v

Resistance = R = 1750 Ω

Required:

Current = I = ?

Formula:

V = IR (Ohm's law)

Solution:

I = V / R

I = 58.1 / 1750

I ≈ 0.03 A

`\rule[225]{225}{2}`