Question

What is the electrostatic force between a 3.00c and 5.00c force that are 2.00 m apart

Answer 1

`q{_(1)` = 3C

`q_(2)`= 5C

r = 2m

where, q1 & q2 are the charges

& r is the distance between the charges.

Step-by-step explanation: According, to the Coulombs law,

F = (k
`q_(1)`
`q_(2)` )/ r²

Therefore, F = {9×
`10^(9)` ×3×5}/
`2^(2)`

F = 33.75 ×
`10^(9)` will be the answer.

Here, k is the constant of proportionality.