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What is the total resistance of a series circuit having a 1202 resistor, a 502 resistor and a 2002 resistor? A. 37Ω C. 250 B. 2002 D. 7Q is this even the right subject to ask?​<…

What is the total resistance of a series circuit having a 1202 resistor, a 502 resistor and a 2002 resistor? A. 37Ω C. 250 B. 2002 D. 7Q is this even the right subject to ask?​<…
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What is the total resistance of a series circuit having a 1202 resistor, a 502 resistor and a 2002 resistor? A. 37Ω C. 250 B. 2002 D. 7Q

is this even the right subject to ask?​

asked
User Jackboberg
by
8.0k points

1 Answer

1 vote

Answer:

Total Resistance = 1202 + 502 + 2002

= 3706 ohms

answered
User Jon Wingfield
by
8.2k points
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