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Determine the equation of the circle with center ( 2 , 3 ) (2,3) containing the point ( 7 , 15 ) (7,15)

1 Answer

7 votes

Answer:

(x -2)² +(y -3)² = 169

Explanation:

You want the equation of the circle through (7, 15) centered at (2, 3).

Circle equation

The standard-form equation for a circle with center (h, k) and radius r is ...

(x -h)² +(y -k)² = r²

The value of r² can be found using the distance formula.

d = √((x2 -x1)² +(y2 -y2)²)

d² = r² = (7 -2)² +(15 -3)² = 5² +12² = 25 +144

r² = 169

The circle equation is ...

(x -2)² +(y -3)² = 169

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Additional comment

You may recognize the triangle shown in the attachment as having side measures that are the Pythagorean triple {5, 12, 13}. That is, once you see coordinate differences of 5 and 12, you know the circle radius is 13, and r² = 13² = 169.

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Determine the equation of the circle with center ( 2 , 3 ) (2,3) containing the point-example-1

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