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Please help me with this question i dont know where to begin with this

Please help me with this question i dont know where to begin with this-example-1
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User Kodvin
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1 Answer

1 vote

Answer:

option D

Explanation:

the values of x are where the graph meets the x-axis.

both values of x are found, in this case, using the quadratic formula,

x = ((-b ± √(b² - 4ac)) ÷ 2a)

our equation is y = 3x² + 5x + 1.

so -5 is -b, b² is (-5)² = +25.

4ac = 4(3)(1) = 12.

√(b² - 4ac) = √(25 - 12) = √13.

2a = 2(3) = 6.

inputting the given equations of x, we get answers of -0.2 and -1.4.

option D is what we want.

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User ZnArK
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