Answer:
Let the height of the tower be h and the distance of the boy from the foot of the tower be d. then tan 32=h/d,
h=d.tan32, take 32 as 30,
h=d.tan30=d/√3 equation 1
When he has walked 8 m towards the tower,
tan 43=h/(d-8)
h=(d-8).tan 43 take 43as 45
h=(d-8).tan45=(d-8)×1=d-8
d/√3=d-8
d-d/√3=8
d(1-1/√3)=8
d(√3-1)=8√3
d=8√3/(√3-1)=8√3(√3+1)/{(√3-1)(√3+1)}=8√3(√3+1)/(3-1)=4√3(√3+1)
h=d/√3=4(√3+1)
Take the value of h from equation 1