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Solve the linear system:

(3.2, 5.6)


(3, 5)


(-0.22, 3.89)


(-1, 7)

Solve the linear system: (3.2, 5.6) (3, 5) (-0.22, 3.89) (-1, 7)-example-1

1 Answer

2 votes

Answer:

-2/9 , 35/9

Explanation:

To solve the system of equations, we can set the two equations equal to each other and solve for $x$:

\begin{align*}

3-4x &= 4+\frac{1}{2}x \\

-\frac{9}{2}x &= 1 \\

x &= -\frac{2}{9}

\end{align*}

Now that we have found $x$, we can substitute it into one of the equations to find $y$:

\begin{align*}

y &= 3-4\left(-\frac{2}{9}\right) \\

y &= \frac{35}{9}

\end{align*}

Therefore, the solution to the system of equations is $\left(-\frac{2}{9},\frac{35}{9}\right)$.

To check if the given points are solutions to the system of equations, we can substitute each point into both equations and see if the equations are satisfied:

\begin{align*}

\text{If } (3.2,5.6): \quad 5.6 &= 3-4(3.2) \quad \checkmark &\quad 5.6 &= 4+\frac{1}{2}(3.2) \quad \checkmark \\

\text{If } (3,5): \quad 5 &= 3-4(3) \quad \checkmark &\quad 5 &= 4+\frac{1}{2}(3) \quad \checkmark \\

\text{If } (-0.22,3.89): \quad 3.89 &= 3-4(-0.22) \quad \checkmark &\quad 3.89 &= 4+\frac{1}{2}(-0.22) \quad \checkmark \\

\text{If } (-1,7): \quad 7 &= 3-4(-1) \quad \checkmark &\quad 7 &= 4+\frac{1}{2}(-1) \quad \checkmark

\end{align*}

All of the given points satisfy both equations, so they are all solutions to the system of equations.

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