Question

13. A balloon has a volume of 30.0 L and a temperature of 15.0 °C. The volume increased to 36.8 L when the

temperature increased. What was the new temperature?

Answer 1

Answer: hopefully this helps the new temperature of the balloon is 30.3 °C.

Explanation:

We can use Charles's law to solve this problem, which states that at constant pressure, the volume of a gas is directly proportional to its temperature. This law is expressed by the equation V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

Using the given values, we can set up the equation as follows:

30.0 L / (15.0 °C + 273.15) = 36.8 L / (T2 + 273.15)

Solving for T2, we get:

T2 = (36.8 L / 30.0 L) * (15.0 °C + 273.15) - 273.15

T2 = 30.3 °C

Therefore, the new temperature of the balloon is 30.3 °C.