Question

Find the solutions of the quadratic equation shown below.
2x^2+9x-56=0

Answer 1

Answer: the solutions to the quadratic equation 2x^2 + 9x - 56 = 0 are x = 2 and x = -8.5.

Explanation:

To solve the quadratic equation 2x^2 + 9x - 56 = 0, we can use the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation.

In this case, a = 2, b = 9, and c = -56. Substituting these values into the quadratic formula, we get:

x = (-9 ± sqrt(9^2 - 4(2)(-56))) / 2(2)

x = (-9 ± sqrt(625)) / 4

x = (-9 ± 25) / 4

The two solutions are:

x = (-9 + 25) / 4 = 4/2 = 2

x = (-9 - 25) / 4 = -34/4 = -8.5

Therefore, the solutions to the quadratic equation 2x^2 + 9x - 56 = 0 are x = 2 and x = -8.5.

Answer 2

The quadratic equation is in the form of ax^2 + bx + c = 0. The solutions to this equation can be found using the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a).

In your case, a = 2, b = 9, and c = -56. Plugging these values into the quadratic formula gives us:

x = (-9 ± √(9^2 - 4 * 2 * -56)) / (2 * 2)

Solving this equation gives us two solutions: x = -8 and x = 3.5.

So the solutions to the equation 2x^2 + 9x - 56 = 0 are x = -8 and x = 3.5.

So the answer is -8