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Equation of the line that passes through (4,8) and (2,-10)

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User Qstebom
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9.1k points

1 Answer

2 votes

Hello !

Answer:


\boxed{\sf y=9x-28}

Explanation:

We are looking for the equation of the line that passes through the two following points :

  • (4,8)
  • (2,-10)

We know that the slope-intercept form of a line is of the form
\sf y=mx+b.

We need to find the coefficients m and b.

Let's replace x and y with 4 and 8, and then with 2 and -10.


\sf \begin{cases}\sf8=4m+b \\\sf -10=2m+b\end{cases}

We obtain a system of two equations to solve.

Let's subtract the second line from the first one :


\sf 8-(-10)=4m+b-(2m+b)\\\iff 18=4m+b-2m-b\\\iff 18=2m\\\iff \boxed{\sf m= (18)/(2)=9 }

Let's substitute 9 for m in the second equation :


\sf -10=2* 9+b\\\iff b+18=-10\\\iff b=-10-18\\\iff \boxed{\sf b=-28}

The equation of the line is :
\boxed{\sf y=9x-28}

Have a nice day ;)

answered
User Fatih Acet
by
8.9k points

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