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Answer: 26.07 g Zn if need to correct sig figs its 26 g Zn
Step-by-step explanation:
use stoichiometry to solve
2.4 X 10^23 atoms Zn X (1mole Zn / 6.02 X 10^23 atoms Zn) X (65.38 g Zn/ 1 mole Zn) =
26.07 g Zn