Answer: 0.737.
Explanation:
Step-1: Find the total number of possible combinations of 3 students that Mr. Spano can choose.
There are 30 students in the class. To find the total number of combinations, we can use the formula nCr = n! / r! (n - r)!
nCr = 30C3
nCr = 30! / 3! (30 - 3)!
nCr = 30!/3!(27!)
nCr = 1140
Step-2: Find the total number of combinations where all 3 students are girls.
There are 18 girls in the class. To find the total number of combinations, we can use the same formula as before:
gC3 = 18C3
gC3 = 18! / 3! (18 - 3)!
gC3 = 18!/3!(15!)
gC3 = 840
Step-3: Compute the probability that all three students are girls.
To compute the probability, we use the following formula:
P(girls) = gC3 / nCr
P(girls) = 840/1140
P(girls) = 0.737
Therefore, the probability that all 3 students Mr. Spano calls on are girls is 0.737.