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A mgcl2 solution contains 10g of mgcl2 calculate the number of magnesium ions in the solution

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Answer:

3.16 x 10^22 magnesium ions

Step-by-step explanation:

The molecular weight of MgCl2 is 95.21 g/mol (24.31 g/mol for magnesium + 2(35.45 g/mol) for chlorine), so 10 g of MgCl2 is equal to:10 g / 95.21 g/mol = 0.105 mol MgCl2Since MgCl2 dissociates into one Mg2+ ion and two Cl- ions in solution, the number of magnesium ions in the solution is equal to half the number of moles of MgCl2:0.105 mol MgCl2 * 0.5 = 0.0525 mol Mg2+To convert this to the number of magnesium ions, we need to multiply by Avogadro's number:0.0525 mol Mg2+ * 6.022 x 10^23 ions/mol = 3.16 x 10^22 magnesium ions

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