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problem 2: a steel pressure tank has an inner diameter of 1.5 m and a wall thickness of 28 mm. if the internal pressure in 5 mpa and the yield strength of the steel in 250 mpa, find the safety factor versus yielding for a) the tresca failure theory, and b) the von mises failure theory.

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Answer:

Step-by-step explanation:

We can use the following equations to calculate the safety factor versus yielding for the two failure theories:

Tresca failure theory: SF_T = σ_yield / σ_max

Von Mises failure theory: SF_VM = σ_yield / σ_eq

where σ_yield is the yield strength of the steel, σ_max is the maximum principal stress, and σ_eq is the equivalent von Mises stress.

To calculate the maximum principal stress, we can use the formula:

σ_max = P_int x r_i / t

where P_int is the internal pressure, r_i is the inner radius (half the diameter), and t is the wall thickness.

a) Tresca failure theory:

First, we need to calculate the maximum principal stress:

σ_max = P_int x r_i / t = 5 MPa x 0.75 m / 0.028 m = 131.25 MPa

Now we can calculate the safety factor using the Tresca failure theory:

SF_T = σ_yield / σ_max = 250 MPa / 131.25 MPa = 1.91

Therefore, the safety factor versus yielding for the Tresca failure theory is 1.91.

b) Von Mises failure theory:

To calculate the equivalent von Mises stress, we can use the formula:

σ_eq = √(σ_1^2 - σ_1σ_2 + σ_2^2)

where σ_1 and σ_2 are the principal stresses. For a thin-walled pressure vessel, the principal stresses can be calculated as:

σ_1 = P_int x r_i / t

σ_2 = 0

Therefore, the equivalent von Mises stress is:

σ_eq = √(σ_1^2 - σ_1σ_2 + σ_2^2) = √(3/2 x σ_1^2) = σ_1 x √3

σ_eq = P_int x r_i / t x √3 = 5 MPa x 0.75 m / 0.028 m x √3 = 226.25 MPa

Now we can calculate the safety factor using the Von Mises failure theory:

SF_VM = σ_yield / σ_eq = 250 MPa / 226.25 MPa = 1.11

Therefore, the safety factor versus yielding for the Von Mises failure theory is 1.11.

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User Ionel Lupu
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